Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by ΔV=V0[γL−γg]Δθ =V[γm−3αg]Δθ Given, γm=182×10−6∕‌°C,αg=10×10−6∕‌°C Δθ=100°C,V=1L ∴ ΔV=1[(182×10−6−3×10×10−6)]×100 ΔV=15.2CC