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AP EAMCET Engineering 2013 Solved Paper
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© examsnet.com
Question : 17
Total: 160
On a temperature scale
Y
, water freezes at
−
160
°
Y
and boils at
−
50
°
Y
. On this
Y
scale, a temperature of
340
K
is
− 160.3° Y
− 96.3° Y
− 86.3° Y
− 76.3° Y
Validate
Solution:
In given condition
Y
+
160
−
50
+
160
=
340
−
273
373
−
273
Y
+
160
110
=
67
100
Y
+
160
=
67
×
110
100
Y
=
73.7
−
160
Y
=
−
86.3
°
Y
© examsnet.com
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