Gauss’s law states that,
ϕ E=EdA= Gauss’s law of magnetism states that the total magnetic flux passing through a bar magnet around its enclosed surface is zero.
ϕ B=BdA=0 According to Faraday’s law of electromagnetic induction,
ε=− .....(I)
The electromotive force in a wire is the line integral, so
ε=∫Edl ....(II)
From equation (I) and (II),
∫Edl=− In a time varying electric field, there exist an additionalcurrent to the conduction current known as displacement current. So, total current across the loop is,
i=ic+id Here,
ic is the conductor current and
id is the displacement current.
Thus, the modified form of the Ampere’s law is,
∮Bdl=µ0i ∮Bdl=µ0[ic+id] Thus, option (3) is correct.