Consider the given circle equations, x2+y2−4x−2y+1=0 ....(I) And, x2+y2−6x−4y+4=0 ....(II) Here, C1=(2,1),C2=(3,2) And, r1=√4+1−1=2 r2=√9+4−4=3 Then C1C2=√(3−2)2+(2−1)2 =√2 And, r1+r2=2+3 =5 This shows that, $C_{1} C_{2} So, the circles intersect at two distinct points. Let the point of intersection be P(x,y) then, P(x,y)=(