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AP EAMCET Engineering 22 Sep 2020 Shift 1 Paper
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© examsnet.com
Question : 4
Total: 160
π
∕
2
∫
0
1
1
+
tan
2020
(
x
)
d
x
=
π
π
2
π
4
0
Validate
Solution:
I
=
π
∕
2
∫
0
d
x
1
+
tan
2020
x
=
π
∕
2
∫
0
cos
2020
x
cos
2020
x
+
sin
2020
x
d
x
.....(i)
On applying property
a
∫
0
f
(
x
)
d
x
=
a
∫
0
f
(
a
−
x
)
d
x
, we get
I
=
π
∕
2
∫
0
sin
2020
x
sin
2020
x
+
cos
2020
x
d
x
....(ii)
On adding Eqs. (i) and (ii), we get
2
I
=
π
∕
2
∫
0
d
x
=
π
2
⇒
I
=
π
4
© examsnet.com
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