=r2 (let)....(ii) are intersecting lines, then on equating the parametric points on lines, we get r1+1=3r2−5 2r1+2=−r2+4 and −3r1+5=4r2+3 So on solving, r1=0 and r2=2 ∴ Point of intersection is A(1,2,5). Now the equation of planc parallel to xy-plane and passes through point A is z=5.