Number between 2000 and 5000 is a 4 digits number. For the multiples of 3 , the sum of digit must be divisible by 3 . There are only 2 ways of selecting the digits so that 4 digit number with the given digits can be formed, i.e. 0,1,2,3 and 0,2,3,4. The number of ways of forming number with digit 0,1,2,3 is 2×3 ! [∵0 and 1 cannot be place on thousand place] The number of ways of forming number with the digit 0,2,3,4 is 3×3![∵0 cannot be place on thousand digit] Hence, the required number of ways =2×3!+3×3! =3!(2+3)=6×5=30