≥0 Case I|x|−2≥0 and |x|−3>0 ⇒|x|≥2 and |x|>3 ⇒|x|>3 ⇒x>3 or x<−3 Case II |x|−2≤0 and |x|−3<0 |x|≤2 and |x|<3 ⇒|x|≤2 −2≤x≤2 |x|−3≠0⇒|x|≠3 ⇒x≠3 and x≠−3 Combining these, we get (−∞,−3)∪[−2,2]∪(3,∞) Finally we write R−[−3,−2)∪(2,3]