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AP ICET 18 Sep 2021 Shift 1 Paper

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Question Numbers : (61 to 65)
In a certain code. the letters of the English alphabet A,B,C,…,ZA, B, C, \dots, Z are given numbers 1,2,31,2,3,…,26\dots, 26 respectively. Then nth n^{\text{th }} letter is coded as rth r^{\text{th }} letter, where 1≤r≤261 \leq r \leq 26 and 1n≡r(mod26)\frac{1}{n} \equiv r \pmod{26}(that is 26 divides 1n−r\frac{1}{n-r} ). For example 9th 9^{\text{th }} letter II is coded as 21st letter U21^{\text{st}}\ \text{letter}\ U, since 99≡2199 \equiv 21 (mod 26). For decoding reverse process is used. Based on this, answer questions 61 to 65 .
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