Given a=41+2+3+x​⇒4a=6+x...(i)I. It gives no additional information on ‘a’ or its relation with x .∴ I alone is not sufficient.Given : x=21​(60−x)....(ii)There are two unknowns (a and x) and we have two distinct equations (i) and(ii) , Hence these can be solved to find x.eg.