Given : 10 < m < 100, m is an integer. I. Given : one digit of m is 3 times the other . ⇒ m can be 13, 31, 26, 62, 39, 93 ∴ I alone is not sufficient. II. Given : Sum of digits in m is 8. ⇒ m can be 17, 71, 26, 62 ∴ II alone is not sufficient. I & II. Both 26 and 62 satisfy both the statements. Thus, we don’t get a unique solution. ∴ I & II together are not sufficient.