Given equation of line is x+y=0 ........(i) and equation of circle is x2+y2+4y=0 ........(ii) On solving Eqs. (i) and (ii), x2+(−x)2+4(−x)=0 ⇒2x2−4x=0 ⇒2x(x−2)=0 ⇒x=0,2and y=0,−2 Now taking option (c) i.e., y2=2x at poing (0,0)⇒0=0 and at point (2,−2) ⇒(−2)2=2(2)⇒4=4 ∴ option (c) is the correct answer.