Given equations are x2+y2=5 ...(i) and y2=4x ...(ii) On solving Eqs. (i) and (ii), we get x=−5,1 at x=−5,y2=−20 (imaginary value) ∴ at x=1,y2=4 ⇒ y = ± 2 Hence, point of intersection are (1,2) and (1,−2). On differentiating Eq. (i) w.r.t. x, we get 2x+2y
dy
dx
=0
dy
dx
=−
x
y
∴m1=(
dy
dx
)(1,2)=−
1
2
And on differentiating Eq. (ii) w.r.t. x, we get 2y