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BITSAT 2012 Solved Question Paper
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© examsnet.com
Question : 102
Total: 150
The value of the determinant
|
265
240
219
240
225
198
219
198
181
|
is
100
779
679
0
Validate
Solution:
Applying
C
1
–
C
2
and
C
2
–
C
3
, we get
Det.
|
25
21
219
15
27
198
21
17
181
|
=
|
4
21
9
−
12
27
−
72
4
17
11
|
[by
C
1
−
C
2
,
C
3
−
10
C
2
]
=
|
4
21
9
0
90
−
45
0
−
4
2
|
[By
R
2
+
3
R
1
,
R
3
−
R
1
]
= 4 (180 - 180) = 0
© examsnet.com
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