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BITSAT 2012 Solved Question Paper
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© examsnet.com
Question : 118
Total: 150
A boy is throwing stones at a target. The probability of hitting the target at any trial is
1
2
. The probability of hitting the target 5th time at the 10th throw is :
5
2
10
63
2
9
10
C
5
2
10
None
Validate
Solution:
The probability of hitting the target 5th time at the 10th throw = P(the probability of hitting the target 4 times in the first 9 throws) × P(the probability of hitting the target at the 10th throw) =
[
9
C
4
(
1
2
)
4
(
1
2
)
5
]
(
1
2
)
=
9
!
4
!
5
!
×
(
1
2
)
10
=
63
2
9
© examsnet.com
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