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BITSAT 2012 Solved Question Paper
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© examsnet.com
Question : 98
Total: 150
If f is an even function and g is an odd function, then the function fog is
an even function
an odd function
neither even nor odd
a periodic function
Validate
Solution:
We have, fog (–x) = f [g (–x)] = f [–g(x)]
(∴ g is odd)
= f[g (x)] (Q f is even)
= fog (x) for all x ∊ R.
∴ fog is an even function.
© examsnet.com
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