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BITSAT 2013 Solved Question Paper
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© examsnet.com
Question : 89
Total: 150
A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box if at least one black ball is to be included in the draw?
64
129
84
None of these
Validate
Solution:
Atleast one black ball can be drawn in the following ways
(i) one black and two other colour balls
=
3
C
1
×
6
C
1
= 3 × 15 = 45
(ii) two black and one other colour balls
=
3
C
2
×
6
C
1
= 3 × 6 = 18
(iii) All the three are black
=
3
C
3
×
6
C
0
= 1
∴ Req. no. of ways = 45 + 18 + 1 = 64
© examsnet.com
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