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BITSAT 2014 Solved Question Paper
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© examsnet.com
Question : 95
Total: 150
If
1
a
,
1
b
,
1
c
are in A. P., then
(
1
a
+
1
b
−
1
c
)
(
1
b
+
1
c
−
1
a
)
is equal to
4
a
c
−
3
b
2
b
2
−
a
c
a
2
b
2
c
2
4
a
c
−
1
b
2
None of these
Validate
Solution:
1
a
−
1
b
=
1
b
−
1
c
∴
(
1
a
+
1
b
−
1
c
)
(
1
b
+
1
c
−
1
a
)
=
(
2
a
−
1
b
)
(
2
c
−
1
b
)
=
4
a
c
−
1
b
(
2
a
−
2
c
)
+
1
b
2
=
4
a
c
−
2
b
(
2
b
)
+
1
b
2
=
4
a
c
−
3
b
2
© examsnet.com
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