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BITSAT 2015 Solved Question Paper
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© examsnet.com
Question : 103
Total: 150
A bag contains 3 red and 3 white balls. Two balls are drawn one by one. The probability that they are of different colours is.
3/10
2/5
3/5
None of these
Validate
Solution:
Let A = event that drawn ball is red
B = event that drawn ball is white
Then AB and BA are two disjoint cases of the given event.
∴ P (AB + BA) = P(AB) + P (BA)
= P (A) P
(
B
A
)
+ P (B) P
(
A
B
)
=
3
6
.
3
5
+
3
6
.
3
5
=
3
5
© examsnet.com
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