Water wets glass and so the angle of contact is zero. For full rise, neglecting the small mass in the meniscus 2πrT = pr2hρg ⇒ h =
2T
rρg
[Since water wets glass, θ = 0°] =
2×0.07
0.25×10−3×1000×9.8
As the tube is only 2 cm above the water and so, water will rise by 2 cm and meet the tube at an angle such that, 2πrT cos θ = πr2h′ρg ⇒ 2T cos θ = h'rρg ⇒ cos θ =
h′rρg
2T
=
2×10−2×0.2×10−3×1000×9.8
2×0.07
The liquid will meet the tube at an angle, θ = 70°