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BITSAT 2017 Solved Question Paper
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© examsnet.com
Question : 6
Total: 150
A coil of inductance 300 mH and resistance
2
Ω
is connected to a source of voltage 2 V. The current reaches half of its steady state value in
0.1 s
0.05 s
0.3 s
0.15 s
Validate
Solution:
The charging of inductance given by.
i
=
i
0
(
1
−
e
−
R
t
L
)
i
0
2
=
i
0
(
1
−
e
−
R
t
L
)
⇒
e
−
R
t
L
=
1
2
Taking log on both sides,
−
R
t
L
=
log
1
−
log
2
⇒
t
=
L
R
log
2
=
300
×
10
−
3
2
×
0.69
⇒
t
=
0.1
s
e
c
© examsnet.com
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