The nuclear reaction is represented as follow: 817O→816O+01n B.E per nucleon of 816O=7.97MeV B.E per nucleon of 017=7.75MeV Energy required to remove a neutron from 817O= ? If mp represents the mass of a proton and mn that of a neutron, the energy required to remove a neutron from 817O is given by, E= energy equivalent of ( mass of 816O+mn− mass of 817O) =(8mp+8mn−7.97×16)+mn−(8mp+9mn−7.75×17) =[7.75×17−7.97×16]MeV =4.23MeV $