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BITSAT 2018 Solved Question Paper
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© examsnet.com
Question : 49
Total: 150
For the reaction taking place at certain temperature
N
H
2
C
O
O
N
H
4
(s) ⇌
2
N
H
3
(g) +
C
O
2
(g)
if equilibrium pressure is 3X bar then
Δ
r
G° would be
– RT ln 9 – 3RT ln X
RT ln 4 – 3RT ln X
– 3RT ln X
None of these
Validate
Solution:
ΔG° = – RT ln
K
P
;
K
P
=
(
2
X
)
2
X = 4
X
3
ΔG° = – RT ln (4
X
3
)
ΔG° = – RT ln 4 – 3RT ln X
© examsnet.com
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