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BITSAT 2018 Solved Question Paper
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© examsnet.com
Question : 64
Total: 150
On passing a current of 1.0 ampere for 16 min and 5 sec through one litre solution of
C
u
C
l
2
, all copper of the solution was deposited at cathode. The strength of
C
u
C
l
2
solution was (Molar mass of Cu = 63.5; Faraday constant = 96,500
C
m
o
l
–
1
)
0.01 N
0.01 M
0.02 M
0.2 N
Validate
Solution:
By Faraday's 1st Law,
W
E
=
q
96500
(where q = it = charge of ion)
we know that no of equivalent
=
W
E
=
i
t
96500
=
1
×
965
96500
=
1
100
(where i = 1 A, t = 16×60+5 = 965 sec.)
Since, we know that
Normality =
no
.
of
equivalent
Volume
(
in
litre
)
=
1
100
1
= 0.01 N
© examsnet.com
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