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BITSAT 2019 Slot 2 Solved Paper
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© examsnet.com
Question : 3
Total: 150
An electron revolves in a circular orbit of radius
r
with angular speed
ω
The magnetic field at the centre of electron orbit is
µ
0
e
ω
π
r
µ
0
e
ω
4
π
r
µ
0
e
2
ω
4
π
r
µ
0
e
ω
2
π
r
Validate
Solution:
Magnetic field at the centre of circular loop,
B
=
µ
0
I
2
r
.......(i)
Period of revolution of electron, where
ω
=
angular velocity of electron
T
=
2
π
ω
where,
ω
=
angular velocity of electron
Current produced due to movement of electron,
I
=
e
T
=
e
2
π
ω
=
e
ω
2
π
On substituting the value of
I
in Eq. (i), we get
B
=
µ
0
2
r
.
e
ω
2
π
⇒
B
=
µ
0
e
ω
4
π
r
© examsnet.com
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