Given, Y=2.2×108m∕s2 Area of cross-section of steel wire, A=4cm2=4×10−4m2 Mass of elevator, m=1000kg The maximum tension in the steel wire that can support elevator is given by T=
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× stress × area of cross - section =
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×2.2×108×4×10−4 =2.2×104N∕m2 If f be the maximum upward acceleration of the elevator, then ⇒T=m(g+f) 2.2×104=1000(10+f) ⇒f=12m∕s2