Let the velocity of the ball just when it leaves the hand is u then applying, v2−u2=2as for upward journey ⇒ −u2=2(−10)×2 ⇒u2=40 Again applying v2−u2=2as for the upward journey of the ball, when the ball is in the hands of the thrower, v2−u2=2as ⇒ 40−0=2(a)0.2 ⇒a=100m∕s2 ∴ F=ma=0.2×100=20N ⇒ N−mg=20 ⇒N=20+2=22N