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BITSAT 2023 Shift 1 Solved Question Paper
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© examsnet.com
Question : 42
Total: 130
If enthalpies of formation of
C
2
H
4
(
g
)
,
CO
2
(
g
)
and
H
2
O
(
l
)
at
25
∘
C
and
1
atm
pressure are 52 , 394 and
−
286
kJ
∕
mol
respectively, the change in enthalpy for combustion of
C
2
H
4
is equal to
−
141.2
kJ
∕
mol
−
1412
kJ
∕
mol
+
14.2
kJ
∕
mol
+
1412
kJ
∕
mol
Validate
Solution:
👈: Video Solution
Enthalpy of formation of
C
2
H
4
,
CO
2
and
H
2
O
are
52
,
−
394
and
−
286
kJ
∕
mol
respectively. (Given)
The reaction is
C
2
H
4
+
3
O
2
→
2
CO
2
+
2
H
2
O
change in enthalpy,
(
∆
H
)
=
∆
H
products
−
∆
H
reactants
=
2
×
(
−
394
)
+
2
×
(
−
286
)
−
(
52
+
0
)
=
−
1412
kJ
∕
mol
© examsnet.com
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