f(x)=1−h(x)....(i) g(x)=1−k(x)......(ii) h(x)=f(x)+1......(iii) j(x)=g(x)+1......(iv) k(x)=j(x)+1.......(v) From Eqs. (i) and (iii), we get f(x)+h(x)=1−h(x)+f(x)+1 ⇒h(x)=1.....(vi) ⇒f(x)=0.....(vii) From Eqs. (ii) and (iv), we get g(x)=1−k(x)=1−(j(x)+1) g(x)=−j(x)......(viii) From Eqs. (iv) and (viii), we get j(x)−g(x)=1 and g(x)=−j(x) ⇒j(x)=