Sequence P is an A.P with a = 11, and common difference 3. So, Pk=11+(k−1)3. Sequence Q is an A.P with third term 103 and common difference - 4. t3=a+2d 103=a+2(−4) or a=111 qk+2=111+(k+1)(−4) qk+2=111−4k−4=107−4k Pk>qk+2 11+(k−1)3>107−4k 8+3k>107−4k 7k>99 k>
99
7
k has to be an integer, so smallest value k can take is 15