Maximum number of widgets delivered in a day is 100 units (C)+70 units (A)+60 units (B)+ 50 units (D), i.e. 280 units Given, total number of widgets delivered is 260 units. This implies 20 units must be decreased from any one of the locations. A−(70,50),B−(60,40),C−(100,70)andD−(50,30) 20 units can be decreased from A,B or D . Demand at location C will be 100 units and supplier first visits C. In the question, it is also given that the route ends at B . C(100 units),_, , B If B's demand is 60 units, D′s demand should be more than 60 units which is not possible. Therefore, B's demand should be 40 units. 20 units is decreased at location B . This implies demand at location A is 70 units and at location D is 50 units. Order will be C(100units)−A(70units)−D(50units)−B(40units). It is given, C−100units−70% A−70units−60% D−50units−60% B−40units−30% Required value =0.7×0.6×0.6×0.3=0.0756=7.56% The answer is option D.