Let the six numbers be a,b,c,d,e,f in ascending order a+b=28 e+f=56 If we want to maximize the average then we have to maximize the value of c and d and maximise e and minimise f e+f=56 As e and f are distinct natural numbers so possible values are 27 and 29 Therefore c and d will be 25 and 26 respectively So average =