BC is the diameter of circle C2 so we can say that ∠BAC=90∘ as angle in the semi circle is 90° Therefore overlapping area =
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2
(AreaofcircleC2)+AreaoftheminorsectormadebeBC in C1 AB=AC=8cm and as ∠BAC=90°, so we can conclude that BC=8√2cm Radius of C2= Half of length of BC=4√2cm Area of C2=π(4√2)2=32πcm2 A is the Centre of C1 and C1 passes through B, so AB is the radius of C1 and is equal to 8cm Area of the minor sector made be BC in C1=
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(AreaofcircleC1)−AreaoftriangleABC=
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π(8)2−(
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2
×8×8)=16π−32cm2 Therefore, Overlapping area between the two circles =
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(AreaofcircleC2)+AreaoftheminorsectormadebeBC in C1 =