Given a and b are the distinct roots of the equation 2x2−6x+k=0 ⇒a+b=−(−6∕2)=3 (Sum of the roots) ⇒ab=k∕2 (Product of the roots) Now, (a+b) and ab are the roots of the quadratic equation x2+px+p=0 ⇒a+b+ab=−p⇒3+k∕2=−p−−(1) ⇒(a+b)(ab)=p⇒3(k∕2)=p−−(2) 3+