Given that the average marks of 4 girls and 6 boys is 24 . Let us assume 'b' is the marks scored by a boy and ' g ' is the marks scored by a girl. ⇒4g+6b=10*24=240−−(1) Given that, b≤g≤2b We need to find the distinct possible values of 2g+6b=2g+240−4g=240−2g. From (1) when b=g⇒10g=240⇒g=24 when b=g∕2⇒7g=240⇒g=240∕7 ⇒240−2gvaries from 240−2*24 to 240−2*240∕7 ⇒ 171,42 to 192⇒ Integer values of 172 to 192⇒21 values.