CAT 2023 Slot 2 Solved Paper

Let the number of total employees in the company be $100 x$, and the total salary of all the employees be $100 y$.It is given that $20\%$ of the employees work in the manufacturing department, and the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company.Hence, the total number of employees in the manufacturing department is $20 x$, and the total salary received by them is $\frac{100 y}{6}$Average salary in the manufacturing department $=\left( \frac{100 y}{6} \cdot 20 x \right) = \frac{5 y}{6 x}$Similarly, the total number of employees in the nonmanufacturing department is $80 x$, and the total salary received by them is $\frac{500 y}{6}$Hence, the average salary in the nonmanufacturing department $=\left( \frac{500 y}{6} \cdot 80 x \right) = \frac{25 y}{24 x}$Hence, the ratio is:- $\left( \frac{5 y}{6 x} \right)$ : $\left( \frac{25 y}{24 x} \right)$$\Rightarrow 120:150=4:5$The correct option is B