CAT 2023 Slot 2 Solved Paper

it is given that the price of a precious stone is directly proportional to the square of its weight. Let the price be denoted by $C$ and the weight is denoted by $W$.Hence, $C \propto W^2 = C = k w^2$ (where k is the proportional constant)Now, Sita has a precious stone weighing 18 units.Therefore, $C = k w^2 = k \cdot 18^2 = 324$If she breaks it into four pieces with each piece having a distinct integer weight, then the difference between the highest and lowest possible values of the total price of the four pieces will be 288000 .To get the lowest possible value of $C$, we will get the weight of the four-piece as close as possible $(3,4,5,6)$. To get the highest value we will try to take three pieces as low as possible, and one is as high as possible (1,2, 3 , 12).Hence, the maximum cost $= k (12^2 + 1^2 + 2^2 + 3^2) = 158 k^2$, and the minimum cost is $k (3^2 + 4^2 + 5^2 + .$ $6^2) = 86 k^2$Hence, the difference is $(158 k^2 - 86 k^2) = 72 k^2$, which is equal to 288000 .$\; \Rightarrow 72 k^2 = 288000$$\; \Rightarrow k^2 = 4000$ Hence, the price of the original stone is $324 k^2 = 324 \times 4000 = 1296000$ The correct option is D