CAT 2023 Slot 3 Solved Paper

It is given that there are exactly 41 numbers, which can be expressed as the power of two, and exist between 8m and 8n, (where m, and n are positive integers, and m<n )
Hence, 23m<41 numbers <23n
Since, m is a positive integer, the least value of m is 1 . Therefore, 23m=23, hence, the 41 numbers between them are 24,25,26,...,244.
Then the lowest possible value of 8n is 245. Hence, the smallest value of n is 245=8n⇒23n=245⇒n=15
Hence, the smallest value of m+n is (15+1)=16
The correct option is D