CAT Exam Model Paper 4 with solutions for free online practice

Let the quantity of total solution be 800 units.
So, quantity of milk is 500 units and water is 300 units.
Now x percent of 800 = 8x units mixture is removed.
The quantity (in units) of milk and water removed is 5x and 3x respectively.
Final concentration of milk (in percentage) is:

500−5x

800

×100
So,30<

500−5x

8

<50
⇒240<500−5x<400
⇒260<−5x<−100
⇒20<x<52