S cannot be at the 1st position as it has been predicted by three persons. Similarly R and Q cannot be at the 2nd and the 3rd positions respectively. So in Prediction 3 the first three positions are definitely incorrect. Now if we assume that exactly two positions are correct in Prediction 3 then P is at the 4th position and T must be at the 5th position. But as a result 4th becomes the only correct position in Prediction 1 which is not possible. Hence all the positions in Prediction 3 must be incorrect. Similarly all the positions in Prediction 1 and Prediction 5 can also be proved incorrect and Prediction 2 and Prediction 4 have exactly two correct positions each. Now it can be answered by observing the options. Alternate solution: The options 'QPSTR’ and ‘QTPSR’ cannot be correct as in both the cases Prediction 4 would have given the correct positions for three runners which would contradict the information given in the question. Similarly the option ‘QPTRS’ cannot be correct as Prediction 4 would have given the correct position for only one runner. The only option left is ‘QPTSR’ which must be correct.