CMAT 2019 Solved Question Paper

let the length of the halls be 'a' and 'a+1' m respectively and height of the halls be 'h' m.
Area of 4 walls of first square hall (A1)=4×a×h‌‌m2
Given, cost of painting is Rs. 5 per sq.m
⇒ cost of painting 4 walls of the first square hall =A1×5=20×a×h.
Given that this cost of painting = Rs. 6000
20×a×h=6000...........(1)
Similarly,Area of 4 walls of second square hall (A2)=4×(a+1)×h‌‌m2
⇒ cost of painting 4 walls of the second square hall =A2×5=4×(a+1)×h×5
=Rs.20+(a+1)×h
Given that this cost of painting = Rs. 6100
20×(a+1)×h=6100............(2)
Dividing (2) with (1), we get

a+1

a

=

6100

6000

a=60
Substituting this value in equation (1), we get
20×60×h=6000
h=5m.
So, the height of the two walls is 5 m.