Total number of 8 -letter words possible using letters S,Y,L,L,A,B,U,S is ‌
8!
2!2!
Statement I: We can find total number of 8 -letter words by considering 2 S's as a single unit and arranging 7 units, i.e. (SS), Y, L,L,A,B,U Total number of ways =‌
7!
2!
Required probability
‌
7!
2!
8!
2!2!
=‌
2
8
=‌
1
4
Therefore, statement I is correct. Statement II: We can find total number of 8-letter words such that L's are at ends by arranging remaining 6 letters in the middle. Total number of ways =‌
6!
2!
Required probability =‌
‌
6!
2!
8!
2!2!
=‌
2
56
=‌
1
28
Therefore, statement II is correct. The answer is option A.