Test Index

CUSAT 2022 BTech Solved Paper Shift 4

© examsnet.com

Question : 2

Total: 200

The position of a particle as a function of time t is given by x(t)=at+bt2−ct3 where, a,b and c are constants. When the particle attains zero acceleration, then its velocity will be

a+‌
b2
4c
a+‌
b2
3c
a+‌
b2
c
a+‌
b2
2c

Go to Question:

Prev Question

Next Question