GIVEN: Numbers between 31 and 491 FORMULA USED: Nthterm=Tn=a+(n–1)d CALCULATION: Numbers which are divisible by both 3 and 5 = Numbers which are divisible by 15. Numbers between 31 and 491 which are divisible by 15 = 45, 60, 75, 90, …………., 480 Let ‘n’ numbers are divisible by 15. Now, 480=45+(n–1)×15 ⇒ 15(n–1)=435 ⇒ (n–1)=29 ⇒ n=30 Hence, total numbers = 30