Given, ten years ago, the elder brother was twice the age of the younger one. Let, the age of younger brother ten years ago = x then, the age of elder brother ten years ago = 2x Present ages: Elder brother = 2x + 10 Younger brother = x + 10 Since, the sum of the present ages of 2 brothers is 50.Thus, x + 10 + 2x + 10 = 50 x = 10 Present age of the elder brother = 2 × 10 + 10 = 30 Hence, 30 years is the correct answer.