GIVEN: Number = 6300 FORMULA USED: If factors of ‘N’ are ap×bq×cr×…….(a=2), then total number of odd factors =(q+1)×(r+1) CALCULATION Factors of 6300 =2×2×3×3×5×5×7=22×32×52×7 Total odd factors = 6300=(2+1)×(2+1)×(1+1) =3×3×2=18 Points to remember 1) If factors of ‘N’ are ap ×bq×cr(a=2), then total number of factors =(p+1)×(q+1)×(r+1) 2) If factors of ‘N’ are ap × bq × cr (a = 2), then total number of odd factors = (q + 1) × (r + 1) 3) If factors of ‘N’ are ap×bq×cr(a=2), then total number of even factors =p×(q+1)×(r+1)