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Question : 6 of 38

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Kishenkant walks 10 kilometres towards North. From there. he walks 6 kilometres towards south. Then he walks 3 km towards east. How far and in which direction is he with reference to his starting point?

5 kilometres West
5 kilometres North-East
7 kilometres East
7 kilometres West

Solution:

Concept:

Net displacement is the vector sum of all movements; use Pythagoras for distance and direction from components.

Explanation:

Step 1: Walk 10 km North, then 6 km South.

Net North-South displacement =

10 - 6 = 4

km North.

Step 2: Walk 3 km East.

So final position relative to start: 4 km North and 3 km East.

Step 3: Distance =

\sqrt{(4)^2 + (3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5

km.

Direction: Since both components are North and East, the direction is North-East.

Answer:

5 kilometres North-East

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