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Question : 7 of 38

Marks: +1, -0

A man leaves for his office from his house. He walks towards East. After moving a distance of

20 {m}

. he turns towards South and walks

10 {m}

. Then he walks

35 {m}

towards the West and further

5 {m}

towards the North. He then turns towards East and walks

15 {m}

. what is the straight distance in metres between his initial and final positions?

0
5
10
Cannot be determined

Solution:

Concept:

Track the net displacement by adding all movement vectors to find the straight-line distance from start.

Explanation:

Let starting point be origin

(0,0)

, East as

+x

, North as

+y

.

Step 1:

20\, \text{m}

East →

(20, 0)

.

Step 2:

10\, \text{m}

South →

(20, -10)

.

Step 3:

35\, \text{m}

West →

(20-35, -10) = (-15, -10)

.

Step 4:

5\, \text{m}

North →

(-15, -10+5) = (-15, -5)

.

Step 5:

15\, \text{m}

East →

(-15+15, -5) = (0, -5)

.

Final position is

5\, \text{m}

directly South of start.

Straight distance is

5

metres.

Answer:

5

metres

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