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EAMCET Engineering 2002 Solved Paper
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© examsnet.com
Question : 35
Total: 200
A body of mass
4
kg
is moving with momentum of
8
kg
ms
−
1
. A force of
0.2
N
acts on it in the direction of motion of the body for 10 seconds. The increase in kinetic energy in joules is
10
8.5
4.5
4
Validate
Solution:
m
=
4
kg
,
p
=
8
kg
m
∕
s
F
=
0.2
N
,
t
=
10
s
e
c
From Newton's IInd law
Force
=
rate of change of momentum
F
=
p
2
−
p
1
t
0.2
=
m
v
−
8
10
2
=
4
×
v
−
8
4
v
=
10
⇒
v
=
5
2
m
∕
s
∴
Final momentum
p
2
=
m
v
=
4
×
5
2
=
10
kg
m
∕
s
Increase in KE,
p
2
2
−
p
1
2
2
m
=
(
10
)
2
−
(
8
)
2
2
×
4
=
100
−
64
8
=
36
8
=
4.5
J
© examsnet.com
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