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EAMCET Engineering 2002 Solved Paper
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© examsnet.com
Question : 36
Total: 200
A body is moving up an inclined plane of angle
θ
with an initial kinetic energy
E
. The coefficient of friction between the plane and the body is
u
. The work done against friction before the body comes to rest is
µ
cos
θ
E
cos
θ
+
s
i
n
θ
E
µ
E
cos
θ
µ
cos
θ
−
s
i
n
θ
µ
E
cos
θ
µ
cos
θ
+
s
i
n
θ
Validate
Solution:
Acceleration of a body up a rough inclined plane
a
=
g
(
µ
cos
θ
+
s
i
n
θ
)
From equation of motion
v
2
=
u
2
−
2
a
s
0
=
u
2
−
2
a
s
u
2
=
2
a
s
Initial
KE
,
E
=
1
2
m
u
2
E
=
1
2
m
(
2
a
s
)
s
=
E
m
a
Work done
W
=
F
⋅
s
=
(
m
g
s
i
n
θ
+
µ
R
)
⋅
E
m
a
=
(
m
g
s
i
n
θ
+
µ
m
g
cos
θ
)
⋅
E
m
(
µ
cos
θ
+
s
i
n
θ
)
=
g
(
s
i
n
θ
+
µ
cos
θ
)
⋅
E
g
(
µ
cos
θ
+
s
i
n
θ
)
=
E
© examsnet.com
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